IOS 开发之NSURL基本操作

时间：2022-06-26 06:01:09 编辑：袖梨来源：一聚教程网

IOS 开发之NSURL基本操作

NSURL其实就是我们在浏览器上看到的网站地址，这不就是一个字符串么，为什么还要在写一个NSURL呢，主要是因为网站地址的字符串都比较复杂，包括很多请求参数，这样在请求过程中需要解析出来每个部门，所以封装一个NSURL，操作很方便：

代码如下

复制代码

NSURL *url = [NSURL URLWithString:@"http://www.baidu.com/s?tn=baiduhome_pg&bs=NSRUL&f=8&rsv_bp=1&rsv_spt=1&wd=NSurl&inputT=2709"];

NSLog(@"Scheme: %@", [url scheme]);

NSLog(@"Host: %@", [url host]);

NSLog(@"Port: %@", [url port]);

NSLog(@"Path: %@", [url path]);

NSLog(@"Relative path: %@", [url relativePath]);

NSLog(@"Path components as array: %@", [url pathComponents]);

NSLog(@"Parameter string: %@", [url parameterString]);

NSLog(@"Query: %@", [url query]);

NSLog(@"Fragment: %@", [url fragment]);

NSLog(@"User: %@", [url user]);

NSLog(@"Password: %@", [url password]);

结果：

代码如下

复制代码

2012-08-29 15:52:23.781 NSurl[3560:f803] Scheme: http

2012-08-29 15:52:32.793 NSurl[3560:f803] Host: www.baidu.com

2012-08-29 15:52:39.102 NSurl[3560:f803] Port: (null)

2012-08-29 15:52:42.590 NSurl[3560:f803] Path: /s

2012-08-29 15:52:52.516 NSurl[3560:f803] Relative path: /s

2012-08-29 15:53:05.576 NSurl[3560:f803] Path components as array: (

"/",

)

2012-08-29 15:53:32.861 NSurl[3560:f803] Parameter string: (null)

2012-08-29 15:53:37.528 NSurl[3560:f803] Query: tn=baiduhome_pg&bs=NSRUL&f=8&rsv_bp=1&rsv_spt=1&wd=NSurl&inputT=2709

2012-08-29 15:53:52.942 NSurl[3560:f803] Fragment: (null)

2012-08-29 15:53:54.539 NSurl[3560:f803] User: (null)

2012-08-29 15:53:57.808 NSurl[3560:f803] Password: (null)