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xcode NSMutableURLRequest,在POST方式下传递参数
时间：2022-06-25 23:51:06 编辑：袖梨 来源：一聚教程网
| 代码如下 | 复制代码 |
| - (IBAction)upload:(id)sender { NSString *post = nil; post = [[NSString alloc] initWithFormat:@"message=%@",@"hello,world."]; NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES]; NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]]; NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init] ; [request setURL:[NSURL URLWithString:@"http://lo**c*alhost/kids/sendimg.php"]]; [request setHTTPMethod:@"POST"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; [request setHTTPBody:postData]; //[NSURLConnection connectionWithRequest:request delegate:self ]; //同步请求的的代码 //returnData就是返回得到的数据 NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil]; NSString *result = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding]; if(returnData) { NSLog(@"SOAP 返回 = %@",result); } else { NSLog(@"error!"); } } |
|
php
| 代码如下 | 复制代码 |
|
print_r($_POST); |
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