xcode NSMutableURLRequest,在POST方式下传递参数

时间：2022-06-25 23:51:06 编辑：袖梨来源：一聚教程网

代码如下

复制代码

- (IBAction)upload:(id)sender {

NSString *post = nil;

post = [[NSString alloc] initWithFormat:@"message=%@",@"hello,world."];

NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];

NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];

NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init] ;

[request setURL:[NSURL URLWithString:@"http://lo**c*alhost/kids/sendimg.php"]];

[request setHTTPMethod:@"POST"];

[request setValue:postLength forHTTPHeaderField:@"Content-Length"];

[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];

[request setHTTPBody:postData];

//[NSURLConnection connectionWithRequest:request delegate:self ];

//同步请求的的代码

//returnData就是返回得到的数据

NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];

NSString *result = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding];

if(returnData)

{

NSLog(@"SOAP 返回 = %@",result);

}

else

{

NSLog(@"error!");

}

}

php

代码如下	复制代码
print_r($_POST); ?> 2014-09-18 15:16:21.346 Test9[31505:ef03] SOAP 返回 = Array ( [message] => hello,world. )

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