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Mysql实现Oracle的INSTR函数的方法实例
时间:2022-11-14 23:36:56 编辑:袖梨 来源:一聚教程网
如果我们的项目要从Oracle迁移到Mysql,但MySQL的instr函数只能查找子串是否在父串中,没法按照出现的次数进行查找。
这里我自己写了一个,以便迁移。当然我这里仅仅针对的是迁移,可能没有完全实现原有函数的细节。
Oracle 里用了几次如下的调用,
SQL> select instr('This is belong to you, but not to me.','to',1,1) as pos from dual;  
  
  
                 POS                                
--------------------                                
                  16                                
  
  
已用时间:  00: 00: 00.00  
SQL> select instr('This is belong to you, but not to me.','to',1,2) as pos from dual;  
  
  
                 POS                                
--------------------                                
                  32                                
  
  
已用时间:  00: 00: 00.00  
SQL> select instr('This is belong to you, but not to me.','belong',-1,1) as pos from dual;  
  
  
                 POS                                
--------------------                                
                   9                                
  
  
已用时间:  00: 00: 00.00  
SQL> select instr('This is belong to you, but not to me.','belong',-1,2) as pos from dual;  
  
  
                 POS                                
--------------------                                
                  0                                
  
  
已用时间:  00: 00: 00.00  
MySQL里效果如下,
mysql> select func_instr_oracle('This is belong to you, but not to me.','to',1,1) as pos;  
+------+  
| pos  |  
+------+  
|   16 |  
+------+  
1 row in set (0.00 sec)  
  
  
mysql> select func_instr_oracle('This is belong to you, but not to me.','to',1,2) as pos;  
+------+  
| pos  |  
+------+  
|   32 |  
+------+  
1 row in set (0.00 sec)  
  
  
mysql> select func_instr_oracle('This is belong to you, but not to me.','belong',-1,1) as pos;  
+------+  
| pos  |  
+------+  
|    9 |  
+------+  
1 row in set (0.00 sec)  
  
  
mysql> select func_instr_oracle('This is belong to you, but not to me.','belong',-1,2) as pos;  
+------+  
| pos  |  
+------+  
|    0 |  
+------+  
1 row in set (0.00 sec)  
附上函数func_instr_oracle的代码:
DELIMITER $$  
  
  
USE `oracle12c`$$  
  
  
DROP FUNCTION IF EXISTS `func_instr_oracle`$$  
  
  
CREATE DEFINER=`root`@`localhost` FUNCTION `func_instr_oracle`(  
    f_str VARCHAR(1000), -- Parameter 1  
    f_substr VARCHAR(100),  -- Parameter 2  
    f_str_pos INT, -- Postion  
    f_count INT UNSIGNED -- Times  
    ) RETURNS INT(10) UNSIGNED  
BEGIN  
      -- Created by ytt. Simulating Oracle instr function.  
      -- Date 2015/12/5.  
      DECLARE i INT DEFAULT 0; -- Postion iterator  
      DECLARE j INT DEFAULT 0; -- Times compare.  
      DECLARE v_substr_len INT UNSIGNED DEFAULT 0; -- Length for Parameter 1.  
      DECLARE v_str_len INT UNSIGNED DEFAULT 0;  -- Length for Parameter 2.  
      SET v_str_len = LENGTH(f_str);   
      SET v_substr_len = LENGTH(f_substr);  
      -- Unsigned.  
      IF f_str_pos > 0 THEN  
        SET i = f_str_pos;  
        SET j = 0;  
        WHILE i <= v_str_len  
        DO  
          IF INSTR(LEFT(SUBSTR(f_str,i),v_substr_len),f_substr) > 0 THEN  
            SET j = j + 1;  
            IF j = f_count THEN  
              RETURN i;  
            END IF;  
          END IF;  
          SET i = i + 1;  
        END WHILE;  
      -- Signed.  
      ELSEIF f_str_pos <0 THEN  
        SET i = v_str_len + f_str_pos+1;  
        SET j = 0;  
        WHILE i <= v_str_len AND i > 0   
        DO  
          IF INSTR(RIGHT(SUBSTR(f_str,1,i),v_substr_len),f_substr) > 0 THEN  
            SET j = j + 1;  
            IF j = f_count THEN  
              RETURN i - v_substr_len + 1;  
            END IF;  
          END IF;  
          SET i = i - 1;  
        END WHILE;  
      -- Equal to 0.  
      ELSE  
        RETURN 0;  
      END IF;  
      RETURN 0;  
    END$$  
  
  
DELIMITER ;MySql中代替Oracle的instr方法
-- Function "INSTR2" DDL CREATE FUNCTION `INSTR2`(v_string varchar(5000), v_delimiter varchar(20), pos int,nth int) RETURNS varchar(5000) begin declare icount int default 0; declare len int default 0; declare len1 int default 0; declare lth int default 0; declare lth1 int default 0; declare str1 varchar(5000) default ''; set len = length(v_string); set len1 = length(v_delimiter); set lth = instr(v_string ,v_delimiter); if lth=0 then set icount = lth; else if pos is null then set icount = lth; elseif pos < 0 then set icount = locate(v_delimiter,v_string,len+pos-1); elseif pos = 0 then set icount = 0; elseif pos = 1 then if nth is null then set icount = lth; elseif nth >=1 then set icount = if (length(substring_index(v_string ,v_delimiter,nth))=0 or length(substring_index(v_string,v_delimiter ,nth))=length(v_string ),0,length(substring_index(v_string ,v_delimiter,nth))+1); else set icount = 0; end if; else if (nth is null) or (nth=1) then set icount = locate(v_delimiter,v_string,pos); elseif nth > 1 then set str1 = substring(v_string,pos) ; set icount = if (length(substring_index(str1 ,v_delimiter,nth))=0 or length(substring_index(str1,v_delimiter ,nth))=length(str1),0,length(substring_index(str1 ,v_delimiter,nth))); if icount<>0 then set icount = icount+pos; end if; end if; end if; end if; return icount; end;
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