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mysql中select into from语句使用例子分析

时间:2014-04-23 00:00:00 编辑:简简单单 来源:转载

表如下所示

 代码如下

SELECT * FROM `test_table_draw` WHERE `borough_id`>=10266 and `borough_id`

<=12354

户型表

SELECT * FROM `test_table_pic` WHERE `borough_id`>=10266 and `borough_id`

<=12354

相册表

创建一个备份表

 代码如下

CREATE TABLE IF NOT EXISTS `test_table_tp` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `pic_url` varchar(200) NOT NULL,
  `pic_thumb` varchar(200) DEFAULT NULL,
  `pic_desc` varchar(200) DEFAULT NULL,
  `borough_id` int(11) NOT NULL,
  `creater` varchar(20) DEFAULT NULL,
  `addtime` int(11) DEFAULT NULL,
  PRIMARY KEY (`id`),
  KEY `borough_id` (`borough_id`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8 AUTO_INCREMENT=97289 ;

语法

 代码如下

Insert into Table2(field1,field2,...) select value1,value2,... from Table1

例子

Insert into test_table_tp select * from test_table_draw where `borough_id`>=10266 and `borough_id`

 

错误提示

 代码如下

INSERT INTO test_table_tp
SELECT *
FROM test_table_draw
WHERE  `borough_id` >=10266
AND  `borough_id`

MySQL 返回:

#1136 - Column count doesn't match value count at row 1

解决

 代码如下

Insert into(id,pic_url,pic_thumb,pic_desc,borough_id,creater,addtime) test_table_tp select id,pic_url,pic_thumb,pic_desc,borough_id,creater,addtimefrom test_table_draw where `borough_id`>=10266 and `borough_id`

<=12354

后来发现上面不对于时又找

 代码如下

Select * Into new_table_name from old_table_name;

测试仪

Select * Into test_table_tp1 from test_table_draw where `borough_id`>=10266 and `borough_id` <=12354


执行后错误

错误
SQL 查询:

 代码如下

SELECT *
INTO test_table_tp
FROM test_table_draw
WHERE  `borough_id` >=10266
AND  `borough_id`
LIMIT 0 , 30

MySQL 返回:

#1327 - Undeclared variable: test_table_tp

网上找到提示要求目标表Table2不存在,因为在插入时会自动创建表Table2,并将Table1中指定字段数据复制到Table2中。

 

 代码如下
Select * Into test_table_tp1 from test_table_draw where `borough_id`>=10266 and `borough_id` <=12354

gg查一下发现原来 mysql 数据库是不支持 SELECT INTO FROM 这种语句的,但是经过研究是可以通过另外一种变通的方法解决这个问题的

 

 代码如下
Create table Table2 (Select * from Table1);

这种语句代替

 代码如下


SELECT vale1, value2, value3 into Table2 from Table1;

下面看一个本人实际操作中的例子吧!

 代码如下


Create table www.111cn.net (Select A.id,B.id as typeId,A.brand,A.quanpin,A.simple from brands as A,cartype as B where A.type=B.name group by A.brand);

这个是关联两个表得出一个查询结果,然后将结果插入到一个新创建的表 www.111cn.net 中。

好了现在我再来做

 代码如下


Create table pic_test (Select *  from test_table_draw where `borough_id`>=10266 and `borough_id` <=12354)

成功了啊

您运行的 SQL 语句已经成功运行了。 (查询花费 0.5645 秒)
SQL 查询:

 代码如下
CREATE TABLE pic_test(
SELECT *
FROM test_table_draw
WHERE  `borough_id` >=10266
AND  `borough_id` <=12354
)

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