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mysql中distinct和group by过滤删除重复行

时间:2013-06-29 00:00:00 编辑:简简单单 来源:原创

下面先来看看例子:

 代码如下

table

id name

1 a

2 b

3 c

4 c

5 b

库结构大概这样,这只是一个简单的例子,实际情况会复杂得多。

比如我想用一条语句查询得到name不重复的所有数据,那就必须使用distinct去掉多余的重复记录。

 代码如下

select distinct name from table

得到的结果是:

name

a

b

c

好像达到效果了,可是,我想要得到的是id值呢?改一下查询语句吧:

 代码如下

select distinct name, id from table

结果会是:

id name

1 a

2 b

3 c

4 c

5 b

distinct怎么没起作用?作用是起了的,不过他同时作用了两个字段,也就是必须得id与name都相同的才会被排除。。。。。。。

我们再改改查询语句:

select id, distinct name from table

现在将完整语句放出:

 代码如下

select *, count(distinct name) from table group by name

结果:

id name count(distinct name)

1 a 1

2 b 1

3 c 1

上面简单但有些地方是不能完成我们的需要的,下面记录了些常用的重复记录操作语句

查询及删除重复记录的方法
(一)
1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断

 代码如下
select * from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)

2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录

 代码如下
delete from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)

3、查找表中多余的重复记录(多个字段)

 代码如下
select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)

4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录

 代码如下
delete from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录

 代码如下
select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

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